分析：做着感觉像脑筋急转弯一样......因为空间的限制，存不下每一个数，所以用数学方法来解.

设t1=Σai - Σbi = aj - bj,t2=Σi*ai - Σi*bi = j*(aj - bj).j是a,b不相等的位置，t2/t1就是答案了.

#include 
     
      #include 
      
       #include 
       
        #include 
        
         using namespace std;int T, n;long long a, b;int main(){    scanf("%d", &T);    while (T--)    {        a = b = 0;        scanf("%d", &n);        for (long long i = 1; i <= n; i++)        {            long long t;            scanf("%lld", &t);            a += t;            b += i*t;        }        for (long long i = 1; i <= n; i++)        {            long long t;            scanf("%lld", &t);            a -= t;            b -= i*t;        }        if (!a)            printf("0\n");        else            printf("1 %lld\n", b / a);    }    return 0;}